10-2x^2=-62

Solution for 10-2x^2=-62 equation:

10-2x^2=-62

We move all terms to the left:

10-2x^2-(-62)=0

We add all the numbers together, and all the variables

-2x^2+72=0

a = -2; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·(-2)·72
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-2}=\frac{-24}{-4}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-2}=\frac{24}{-4}
=-6
$